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Let’s check out your problem:
Divide.
\newline
2
1
2
2\frac{1}{2}
2
2
1
÷
\div
÷
3
1
3
3\frac{1}{3}
3
3
1
= _____
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Math Problems
Grade 7
Divide mixed numbers
Full solution
Q.
Divide.
\newline
2
1
2
2\frac{1}{2}
2
2
1
÷
\div
÷
3
1
3
3\frac{1}{3}
3
3
1
= _____
Convert to Improper Fractions:
Convert mixed numbers to improper
fractions
for easier division.
\newline
2
1
2
=
(
2
×
2
+
1
)
/
2
=
5
2
2 \frac{1}{2} = (2\times2 + 1)/2 = \frac{5}{2}
2
2
1
=
(
2
×
2
+
1
)
/2
=
2
5
\newline
3
1
3
=
(
3
×
3
+
1
)
/
3
=
10
3
3 \frac{1}{3} = (3\times3 + 1)/3 = \frac{10}{3}
3
3
1
=
(
3
×
3
+
1
)
/3
=
3
10
Set Up Division:
Set up the division of the two improper fractions.
(
5
2
)
÷
(
10
3
)
(\frac{5}{2}) \div (\frac{10}{3})
(
2
5
)
÷
(
3
10
)
Multiply by Reciprocal:
Multiply by the reciprocal of the divisor to solve the division.
\newline
(
5
2
)
×
(
3
10
)
=
15
20
(\frac{5}{2}) \times (\frac{3}{10}) = \frac{15}{20}
(
2
5
)
×
(
10
3
)
=
20
15
Simplify Fraction:
Simplify the
fraction
.
15
20
=
3
4
\frac{15}{20} = \frac{3}{4}
20
15
=
4
3
More problems from Divide mixed numbers
Question
Find `x` value
\newline
2
x
−
2
=
0
2x-2=0
2
x
−
2
=
0
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Posted 8 months ago
Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
x
x
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2
+
8
2+8
2
+
8
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6
+
12
6+12
6
+
12
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Question
Multiply.
\newline
(
3
5
)
×
(
1
6
)
=
(\frac{3}{5})\times(\frac{1}{6})=
(
5
3
)
×
(
6
1
)
=
\newline
Submit
\newline
Get help
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Posted 8 months ago
Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
.
x.
x
.
Get tutor help
Posted 8 months ago
Question
Simplify to a single power of
3
3
3
:
\newline
3
5
×
3
2
3^{5} \times 3^{2}
3
5
×
3
2
\newline
Answer:
3
□
3 ^\square
3
□
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Posted 9 months ago
Question
Simplify to a single power of
6
6
6
:
\newline
6
3
⋅
6
2
6^{3} \cdot 6^{2}
6
3
⋅
6
2
\newline
Answer:
6
□
6 ^\square
6
□
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Posted 9 months ago
Question
What value of
z
z
z
makes the equation below true?
\newline
9
z
−
2
=
79
9 z-2=79
9
z
−
2
=
79
\newline
3
3
3
\newline
9
9
9
\newline
13
13
13
\newline
79
79
79
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Posted 8 months ago
Question
What value of
y
y
y
makes the equation below true?
\newline
5
y
+
2
=
17
5 y+2=17
5
y
+
2
=
17
\newline
2
2
2
\newline
3
3
3
\newline
6
6
6
\newline
17
17
17
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Posted 8 months ago
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