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Let’s check out your problem:
Divide.
\newline
1
3
÷
4
=
_
_
_
_
\frac{1}{3} \div 4 = \_\_\_\_
3
1
÷
4
=
____
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Math Problems
Grade 7
Divide fractions
Full solution
Q.
Divide.
\newline
1
3
÷
4
=
_
_
_
_
\frac{1}{3} \div 4 = \_\_\_\_
3
1
÷
4
=
____
Set up division fraction:
Set up the division as a
fraction
.
1
3
÷
4
\frac{1}{3} \div 4
3
1
÷
4
can be written as
(
1
3
)
/
4
(\frac{1}{3}) / 4
(
3
1
)
/4
.
Convert whole number:
Convert the
whole number
into a fraction.
4
4
4
can be written as
4
1
\frac{4}{1}
1
4
, so the expression becomes
(
1
3
)
/
(
4
1
)
\left(\frac{1}{3}\right) / \left(\frac{4}{1}\right)
(
3
1
)
/
(
1
4
)
.
Multiply by reciprocal:
Multiply by the reciprocal of the divisor.
\newline
To divide by a fraction, multiply by its reciprocal. So,
(
1
3
)
×
(
1
4
)
(\frac{1}{3}) \times (\frac{1}{4})
(
3
1
)
×
(
4
1
)
.
Multiply numerators and denominators:
Multiply the numerators and the denominators.
1
×
1
=
1
1 \times 1 = 1
1
×
1
=
1
and
3
×
4
=
12
3 \times 4 = 12
3
×
4
=
12
, so the answer is
1
12
\frac{1}{12}
12
1
.
More problems from Divide fractions
Question
Find `x` value
\newline
2
x
−
2
=
0
2x-2=0
2
x
−
2
=
0
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Posted 8 months ago
Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
x
x
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2
+
8
2+8
2
+
8
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6
+
12
6+12
6
+
12
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Question
Multiply.
\newline
(
3
5
)
×
(
1
6
)
=
(\frac{3}{5})\times(\frac{1}{6})=
(
5
3
)
×
(
6
1
)
=
\newline
Submit
\newline
Get help
Get tutor help
Posted 8 months ago
Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
.
x.
x
.
Get tutor help
Posted 8 months ago
Question
Simplify to a single power of
3
3
3
:
\newline
3
5
×
3
2
3^{5} \times 3^{2}
3
5
×
3
2
\newline
Answer:
3
□
3 ^\square
3
□
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Posted 9 months ago
Question
Simplify to a single power of
6
6
6
:
\newline
6
3
⋅
6
2
6^{3} \cdot 6^{2}
6
3
⋅
6
2
\newline
Answer:
6
□
6 ^\square
6
□
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Posted 9 months ago
Question
What value of
z
z
z
makes the equation below true?
\newline
9
z
−
2
=
79
9 z-2=79
9
z
−
2
=
79
\newline
3
3
3
\newline
9
9
9
\newline
13
13
13
\newline
79
79
79
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Posted 8 months ago
Question
What value of
y
y
y
makes the equation below true?
\newline
5
y
+
2
=
17
5 y+2=17
5
y
+
2
=
17
\newline
2
2
2
\newline
3
3
3
\newline
6
6
6
\newline
17
17
17
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Posted 8 months ago
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