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Let’s check out your problem:
Divide.
\newline
1
12
÷
4
=
_
_
_
_
\frac{1}{12} \div 4 = \_\_\_\_
12
1
÷
4
=
____
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Math Problems
Grade 7
Divide fractions
Full solution
Q.
Divide.
\newline
1
12
÷
4
=
_
_
_
_
\frac{1}{12} \div 4 = \_\_\_\_
12
1
÷
4
=
____
Set up division as fraction:
First, we need to set up the division as a
fraction
problem. We write it as
(
1
12
)
÷
4
(\frac{1}{12}) \div 4
(
12
1
)
÷
4
.
Use reciprocal for division:
Next, dividing by a number is the same as multiplying by its reciprocal. So,
(
1
12
)
÷
4
(\frac{1}{12}) \div 4
(
12
1
)
÷
4
becomes
(
1
12
)
×
(
1
4
)
(\frac{1}{12}) \times (\frac{1}{4})
(
12
1
)
×
(
4
1
)
.
Multiply numerators and denominators:
Now, multiply the numerators and the denominators.
1
×
1
=
1
1 \times 1 = 1
1
×
1
=
1
and
12
×
4
=
48
12 \times 4 = 48
12
×
4
=
48
. So,
(
1
12
)
×
(
1
4
)
=
1
48
(\frac{1}{12}) \times (\frac{1}{4}) = \frac{1}{48}
(
12
1
)
×
(
4
1
)
=
48
1
.
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\newline
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Multiply.
\newline
(
3
5
)
×
(
1
6
)
=
(\frac{3}{5})\times(\frac{1}{6})=
(
5
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)
×
(
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)
=
\newline
Submit
\newline
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Question
Simplify to a single power of
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3
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:
\newline
3
5
×
3
2
3^{5} \times 3^{2}
3
5
×
3
2
\newline
Answer:
3
□
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3
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Question
Simplify to a single power of
6
6
6
:
\newline
6
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⋅
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6
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\newline
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Question
What value of
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z
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\newline
9
z
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79
9 z-2=79
9
z
−
2
=
79
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3
3
3
\newline
9
9
9
\newline
13
13
13
\newline
79
79
79
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Question
What value of
y
y
y
makes the equation below true?
\newline
5
y
+
2
=
17
5 y+2=17
5
y
+
2
=
17
\newline
2
2
2
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\newline
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17
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