Direction (Q. Nos. 25−30) This section contains 6 questions. When fom 0 to 9 (both inclusive).25 The function f:[2,∞)→Y defined by f(x)==x2−4x+5 is both one-one and onto, if Y∈[a,∞), then the value of a is26 If f(x)=(34a−7)x3+(a−3)x2+x+5 is one-one function, where a∈[λ,μ], then the value of ∣λ−μ∣ is27 Let f be a one-one function with domain {x,y,z} and range {1,2,3}. It is given the exactly one of the following statements is true and remaining two are false, f(x)==x2−4x+50, then f(x)==x2−4x+51 is28. If f(x)==x2−4x+52, number of functions from f(x)==x2−4x+53 to f(x)==x2−4x+54 such that range contains exactly 3 elements is f(x)==x2−4x+55, then the value of f(x)==x2−4x+56 is29 If f(x)==x2−4x+57, then f(x)==x2−4x+58 is equal to30 If f(x)==x2−4x+59 be a polynomial of degree 4 with leading coefficient 1 satisfying Y∈[a,∞)0, Y∈[a,∞)1, where Y∈[a,∞)2, then the value of Y∈[a,∞)3 is
Q. Direction (Q. Nos. 25−30) This section contains 6 questions. When fom 0 to 9 (both inclusive).25 The function f:[2,∞)→Y defined by f(x)==x2−4x+5 is both one-one and onto, if Y∈[a,∞), then the value of a is26 If f(x)=(34a−7)x3+(a−3)x2+x+5 is one-one function, where a∈[λ,μ], then the value of ∣λ−μ∣ is27 Let f be a one-one function with domain {x,y,z} and range {1,2,3}. It is given the exactly one of the following statements is true and remaining two are false, f(x)==x2−4x+50, then f(x)==x2−4x+51 is28. If f(x)==x2−4x+52, number of functions from f(x)==x2−4x+53 to f(x)==x2−4x+54 such that range contains exactly 3 elements is f(x)==x2−4x+55, then the value of f(x)==x2−4x+56 is29 If f(x)==x2−4x+57, then f(x)==x2−4x+58 is equal to30 If f(x)==x2−4x+59 be a polynomial of degree 4 with leading coefficient 1 satisfying Y∈[a,∞)0, Y∈[a,∞)1, where Y∈[a,∞)2, then the value of Y∈[a,∞)3 is
Identify total elements: Identify the total number of elements in sets A and B.n(A) = 4 (elements in set A)n(B) = 5 (elements in set B)
Calculate ways to choose: Calculate the number of ways to choose 3 elements from set B to form the range of the function.Number of ways to choose 3 elements from 5 = C(5,3)=3!×(5−3)!5!=10
Determine surjective functions: Determine the number of surjective (onto) functions from a 4-element set to a 3-element set.Each element in A must map to an element in the chosen 3-element subset of B. The number of surjective functions is given by the Stirling numbers of the second kind, multiplied by 3! (to account for permutations of the range).Number of surjective functions = 3!×S(4,3) where S(n,k) is the Stirling number of the second kind.S(4,3)=6 (from Stirling numbers table)Total surjective functions = 6×3!=36
Calculate total functions: Calculate the total number of functions k.Since there are 10 ways to choose the 3 elements from B and 36 surjective functions for each choice,k=10×36=360
Calculate value of (k)/(60): Calculate the value of (k)/(60).(k)/(60)=60360=6
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