We want to factor the following expression:9x6+6x3y+y2Which pattern can we use to factor the expression?U and V are either constant integers or single-variable expressions.Choose 1 answer:(A) (U+V)2 or (U−V)2(B) (U+V)(U−V)(C) We can't use any of the patterns.
Q. We want to factor the following expression:9x6+6x3y+y2Which pattern can we use to factor the expression?U and V are either constant integers or single-variable expressions.Choose 1 answer:(A) (U+V)2 or (U−V)2(B) (U+V)(U−V)(C) We can't use any of the patterns.
Recognize the structure: Recognize the structure of the given expression.The given expression is 9x6+6x3y+y2. We can observe that the first term is a perfect square (3x3)2, the last term is a perfect square (y)2, and the middle term is twice the product of the square roots of the first and last terms (2×3x3×y).
Identify the factoring pattern: Identify the factoring pattern.The structure of the expression matches the pattern of a perfect square trinomial, which is (A+B)2=A2+2AB+B2 or (A−B)2=A2−2AB+B2. In this case, since the middle term is positive, we will use the (A+B)2 pattern.
Apply the factoring pattern: Apply the factoring pattern to the expression.We can write the expression as (3x3+y)2 because (3x3)2=9x6, 2⋅3x3⋅y=6x3y, and y2=y2. Therefore, the factored form of the expression is (3x3+y)2.
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