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We want to factor the following expression:

9x^(6)+6x^(3)y+y^(2)
Which pattern can we use to factor the expression?

U and 
V are either constant integers or single-variable expressions.
Choose 1 answer:
(A) 
(U+V)^(2) or 
(U-V)^(2)
(B) 
(U+V)(U-V)
(c) We can't use any of the patterns.

We want to factor the following expression:\newline9x6+6x3y+y2 9 x^{6}+6 x^{3} y+y^{2} \newlineWhich pattern can we use to factor the expression?\newlineU U and V V are either constant integers or single-variable expressions.\newlineChoose 11 answer:\newline(A) (U+V)2 (U+V)^{2} or (UV)2 (U-V)^{2} \newline(B) (U+V)(UV) (U+V)(U-V) \newline(C) We can't use any of the patterns.

Full solution

Q. We want to factor the following expression:\newline9x6+6x3y+y2 9 x^{6}+6 x^{3} y+y^{2} \newlineWhich pattern can we use to factor the expression?\newlineU U and V V are either constant integers or single-variable expressions.\newlineChoose 11 answer:\newline(A) (U+V)2 (U+V)^{2} or (UV)2 (U-V)^{2} \newline(B) (U+V)(UV) (U+V)(U-V) \newline(C) We can't use any of the patterns.
  1. Recognize the structure: Recognize the structure of the given expression.\newlineThe given expression is 9x6+6x3y+y29x^{6} + 6x^{3}y + y^{2}. We can observe that the first term is a perfect square (3x3)2(3x^{3})^2, the last term is a perfect square (y)2(y)^2, and the middle term is twice the product of the square roots of the first and last terms (2×3x3×y)(2 \times 3x^{3} \times y).
  2. Identify the factoring pattern: Identify the factoring pattern.\newlineThe structure of the expression matches the pattern of a perfect square trinomial, which is (A+B)2=A2+2AB+B2(A + B)^2 = A^2 + 2AB + B^2 or (AB)2=A22AB+B2(A - B)^2 = A^2 - 2AB + B^2. In this case, since the middle term is positive, we will use the (A+B)2(A + B)^2 pattern.
  3. Apply the factoring pattern: Apply the factoring pattern to the expression.\newlineWe can write the expression as (3x3+y)2(3x^{3} + y)^2 because (3x3)2=9x6(3x^{3})^2 = 9x^{6}, 23x3y=6x3y2 \cdot 3x^{3} \cdot y = 6x^{3}y, and y2=y2y^2 = y^{2}. Therefore, the factored form of the expression is (3x3+y)2(3x^{3} + y)^2.

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