Determine whether (2,1,8) is a solution to the system. {:[4x-4y-5z=,-36],[2x-5y+5z=,39],[-14 x-3y+10 z=,49]:}

Substitute Equations: Step 1: Substitute x=2, y=1, z=8 into the first equation 4x - 4y - 5z = -36. Calculation: 4(2) - 4(1) - 5(8) = 8 - 4 - 40 = -36.Calculate First Equation: Step 2: Substitute x=2, y=1, z=8 into the second equation 2x - 5y + 5z = 39. Calculation: 2(2) - 5(1) + 5(8) = 4 - 5 + 40 = 39.Calculate Second Equation: Step 3: Substitute x=2, y=1, z=8 into the third equation -14x - 3y + 10z = 49. Calculation: -14(2) - 3(1) + 10(8) = -28 - 3 + 80 = 49.

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Determine whether
(2,1,8) is a solution to the system.

{:[4x-4y-5z=,-36],[2x-5y+5z=,39],[-14 x-3y+10 z=,49]:}

Determine whether $(2,1,8)$ is a solution to the system. $\newline$ $\begin{array}{rr} 4 x-4 y-5 z= & -36 \\ 2 x-5 y+5 z= & 39 \\ -14 x-3 y+10 z= & 49 \end{array}$

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Q. Determine whether

(2,1,8)

is a solution to the system.

\newline

\begin{array}{rr} 4 x-4 y-5 z= & -36 \\ 2 x-5 y+5 z= & 39 \\ -14 x-3 y+10 z= & 49 \end{array}

Substitute Equations: Step $1$ : Substitute $x=2$ , $y=1$ , $z=8$ into the first equation $4x - 4y - 5z = -36$ . $\newline$ Calculation: $4(2) - 4(1) - 5(8) = 8 - 4 - 40 = -36$ .
Calculate First Equation: Step $2$ : Substitute $x=2$ , $y=1$ , $z=8$ into the second equation $2x - 5y + 5z = 39$ . $\newline$ Calculation: $2(2) - 5(1) + 5(8) = 4 - 5 + 40 = 39$ .
Calculate Second Equation: Step $3$ : Substitute $x=2$ , $y=1$ , $z=8$ into the third equation $-14x - 3y + 10z = 49$ . $\newline$ Calculation: $-14(2) - 3(1) + 10(8) = -28 - 3 + 80 = 49$ .