Determine the value of y, if x is 17 . y=sqrt(x-1) Answer: y=

Substitute x = 17: First, we need to substitute the value of x into the equation y = sqrt(x - 1). Substitute x = 17 into the equation: y = sqrt(17 - 1).Perform subtraction: Now, we perform the subtraction inside the square root: 17 - 1 = 16. So, y = sqrt(16).Find square root: Next, we find the square root of 16, which is a perfect square. The square root of 16 is 4, so y = 4.

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Determine the value of
y, if
x is 17 .

y=sqrt(x-1)
Answer:
y=

Determine the value of $y$ , if $x$ is $17$ . $\newline$ $y=\sqrt{x-1}$ $\newline$ Answer: $y=$

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Precalculus

Find the roots of factored polynomials

Full solution

Q. Determine the value of

y

, if

x

17

\newline

y=\sqrt{x-1}

\newline

Answer:

y=

Substitute $x = 17$ : First, we need to substitute the value of $x$ into the equation $y = \sqrt{x - 1}$ . $\newline$ Substitute $x = 17$ into the equation: $y = \sqrt{17 - 1}$ .
Perform subtraction: Now, we perform the subtraction inside the square root: $17 - 1 = 16$ . So, $y = \sqrt{16}$ .
Find square root: Next, we find the square root of $16$ , which is a perfect square. $\newline$ The square root of $16$ is $4$ , so $y = 4$ .