Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Determine the smallest integer value of 
x in the solution of the following inequality.

5x+9 >= 13
Answer: 
x=

Determine the smallest integer value of x x in the solution of the following inequality.\newline5x+913 5 x+9 \geq 13 \newlineAnswer: x= x=

Full solution

Q. Determine the smallest integer value of x x in the solution of the following inequality.\newline5x+913 5 x+9 \geq 13 \newlineAnswer: x= x=
  1. Subtract 99: Subtract 99 from both sides of the inequality to isolate the term with xx.\newline5x+991395x + 9 - 9 \geq 13 - 9
  2. Simplify sides: Simplify both sides of the inequality. 5x45x \geq 4
  3. Divide by 55: Divide both sides of the inequality by 55 to solve for xx.5x545\frac{5x}{5} \geq \frac{4}{5}
  4. Simplify inequality: Simplify the inequality to find the smallest value of xx.x45x \geq \frac{4}{5}Since we are looking for the smallest integer value of xx, we need to round up because xx must be greater than or equal to 45\frac{4}{5}.
  5. Determine integer value: Determine the smallest integer greater than or equal to 45\frac{4}{5}. The smallest integer greater than or equal to 45\frac{4}{5} is 11. x=1x = 1

More problems from Solve logarithmic equations with multiple logarithms