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Determine the largest integer value of
x in the solution of the following inequality.

5x-3 <= -20
Answer:
x=

Determine the largest integer value of $x$ in the solution of the following inequality. $\newline$ $5 x-3 \leq-20$ $\newline$ Answer: $x=$

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Solve logarithmic equations with multiple logarithms

Full solution

Q. Determine the largest integer value of

x

in the solution of the following inequality.

\newline

5 x-3 \leq-20

\newline

Answer:

x=

Add $3$ to isolate $x$ : Add $3$ to both sides of the inequality to isolate the term with $x$ on one side. $\newline$ $5x - 3 + 3 \leq -20 + 3$ $\newline$ $5x \leq -17$
Divide by $5$ : Divide both sides of the inequality by $5$ to solve for $x$ . $\frac{5x}{5} \leq \frac{-17}{5}$ $x \leq \frac{-17}{5}$
Consider integer part: Since we are looking for the largest integer value of $x$ , we need to consider the integer part of $-\frac{17}{5}$ . The integer part of $-\frac{17}{5}$ is $-4$ because $-3.4$ (which is $-\frac{17}{5}$ ) rounds down to $-4$ when looking for the largest integer less than or equal to $-3.4$ . $\newline$ $x \leq -4$

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