Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.4x+y=4−6x−y=−6One SolutionInfinitely Many SolutionsNo Solutions
Q. Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.4x+y=4−6x−y=−6One SolutionInfinitely Many SolutionsNo Solutions
Write Equations: Write down the system of equations to analyze. {4x+y=4−6x−y=−6
Add and Eliminate y: Attempt to solve the system by adding the two equations together to eliminate y.Adding 4x+y=4 and −6x−y=−6 gives us:4x+y−6x−y=4−6This simplifies to:−2x=−2
Solve for x: Solve for x by dividing both sides of the equation by \(-2").\(-2x / −2 = −2 / −2")This gives us:x = \(1")
Substitute x into Equation: Substitute x=1 into one of the original equations to solve for y. Using the first equation 4x+y=4: 4(1)+y=44+y=4 Subtract 4 from both sides to solve for y: y=4−4y=0
Check Validity: Check the solution (x=1,y=0) in the second equation to ensure it is valid.Substitute x=1 and y=0 into −6x−y=−6:−6(1)−0=−6−6=−6The solution satisfies the second equation as well.
Final Solution: Since we have found a single solution (x=1,y=0) that satisfies both equations, the system has exactly one solution.