Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution. {:[-x+y=3],[-2x+2y=3]:} No Solutions Infinitely Many Solutions One Solution

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Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.  {:[-x+y=3],[-2x+2y=3]:} No Solutions Infinitely Many Solutions One Solution

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Analyze Equations: Analyze the system of equations. We have the system: 1. -x + y = 3 2. -2x + 2y = 3 We will first look for any obvious inconsistencies or dependencies between the two equations.Compare Equations: Compare the two equations. We notice that the second equation is just the first equation multiplied by 2. This means that the two equations are not independent; they are essentially the same line.Determine Solution Type: Determine the type of solution. Since both equations represent the same line, every point that lies on the first line also lies on the second line. Therefore, the system does not have a unique solution or no solution; instead, it has infinitely many solutions.

Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution. $\newline$ $\begin{array}{r} -x+y=3 \\ -2 x+2 y=3 \end{array}$ $\newline$ No Solutions $\newline$ Infinitely Many Solutions $\newline$ One Solution

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Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.\newline−x+y=3−2x+2y=3 \begin{array}{r} -x+y=3 \\ -2 x+2 y=3 \end{array} −x+y=3−2x+2y=3​\newlineNo Solutions\newlineInfinitely Many Solutions\newlineOne Solution

Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution. $\newline$ $\begin{array}{r} -x+y=3 \\ -2 x+2 y=3 \end{array}$ $\newline$ No Solutions $\newline$ Infinitely Many Solutions $\newline$ One Solution