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Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.

{:[-x+2y=-1],[5x-10 y=5]:}
One Solution
Infinitely Many Solutions
No Solutions

Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.\newlinex+2yamp;=15x10yamp;=5 \begin{aligned} -x+2 y & =-1 \\ 5 x-10 y & =5 \end{aligned} \newlineOne Solution\newlineInfinitely Many Solutions\newlineNo Solutions

Full solution

Q. Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.\newlinex+2y=15x10y=5 \begin{aligned} -x+2 y & =-1 \\ 5 x-10 y & =5 \end{aligned} \newlineOne Solution\newlineInfinitely Many Solutions\newlineNo Solutions
  1. Write Equations: Write down the system of equations.\newlineWe have the system:\newlinex+2y=1,(-x + 2y = -1,(\newline5x - 10y = 5\)
  2. Simplify Equations: Look for a way to simplify or manipulate the equations to make them easier to compare.\newlineNotice that the second equation can be simplified by dividing all terms by 55.\newlineSimplified second equation: x2y=1x - 2y = 1
  3. Compare Equations: Compare the simplified second equation with the first equation.\newlineThe first equation is: x+2y=1-x + 2y = -1\newlineThe simplified second equation is: x2y=1x - 2y = 1\newlineWe can see that the coefficients of xx and yy in the second equation are the negatives of those in the first equation, and the constants are also negatives of each other.
  4. Determine Relationship: Determine the relationship between the two equations.\newlineSince the two equations are multiples of each other (by 1-1), they represent the same line. Therefore, every solution to one equation is also a solution to the other.
  5. Conclude Solutions: Conclude the number of solutions the system has.\newlineBecause the two equations represent the same line, there are infinitely many points that satisfy both equations. Hence, the system has infinitely many solutions.