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Correct$\newline$Given $\newline$$f(x)$, find $\newline$$g(x)$ and $\newline$$h(x)$ such that $\newline$$f(x)=g(h(x))$ and neither $\newline$$g(x)$ nor $\newline$$h(x)$ is solely $\newline$$x$.$\newline$$f(x)=\sqrt{-x+3}-1$$\newline$Answer$\newline$$\{:[g(x)=\square],[h(x)=\square],[\square]:\}$