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The graph of a sinusoidal function intersects its midline at 
(0,-6) and then has a minimum point at 
(2.5,-9).
Write the formula of the function, where 
x is entered in radians.

f(x)=

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The graph of a sinusoidal function intersects its midline at (0,6) (0,-6) and then has a minimum point at (2.5,9) (2.5,-9) .\newlineWrite the formula of the function, where x x is entered in radians.\newlinef(x)= f(x)= \square

Full solution

Q. The graph of a sinusoidal function intersects its midline at (0,6) (0,-6) and then has a minimum point at (2.5,9) (2.5,-9) .\newlineWrite the formula of the function, where x x is entered in radians.\newlinef(x)= f(x)= \square
  1. Determine Midline and Amplitude: Determine the midline and amplitude of the sinusoidal function. The midline is given by the yy-coordinate of the intersection with the midline, which is 6-6. The minimum point is at (2.5,9)(2.5, -9). The amplitude is the distance from the midline to the minimum or maximum point. Here, the distance from 6-6 to 9-9 is 33, so the amplitude is 33.
  2. Identify Period and Phase Shift: Identify the period and phase shift. Since the function reaches a minimum at x=2.5x = 2.5, and this is the first minimum after crossing the midline at x=0x = 0, we can determine that the period is 4×2.54 \times 2.5, which is 1010. There is no horizontal shift since the sinusoidal function crosses the midline at x=0x = 0.
  3. Write Sinusoidal Function: Write the sinusoidal function formula. We know the function has a minimum at (2.5,9)(2.5, -9) and crosses the midline at (0,6)(0, -6). Since it's a minimum, we use a negative cosine function. The formula is:\newlinef(x)=3cos(π5x)6f(x) = -3\cos\left(\frac{\pi}{5}x\right) - 6

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