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Consider the following problem:
The number of people in Bernardo's social network is increasing at a rate of 
r(t)=-2(t-3)^(2)+23 people per month (where 
t is the time in months since Bernardo set up the network). At time 
t=4 months, Bernardo had 80 people in his social network. How many people were in Bernardo's social network at the end of the 
6^("th ") month?
Which expression can we use to solve the problem?
Choose 1 answer:
(A) 
int_(4)^(6)r(t)dt
(B) 
r(6)
(C) 
int_(0)^(6)r(t)dt
(D) 
80+int_(4)^(6)r(t)dt

Consider the following problem:\newlineThe number of people in Bernardo's social network is increasing at a rate of r(t)=2(t3)2+23 r(t)=-2(t-3)^{2}+23 people per month (where t t is the time in months since Bernardo set up the network). At time t=4 t=4 months, Bernardo had 8080 people in his social network. How many people were in Bernardo's social network at the end of the 6th  6^{\text {th }} month?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) 46r(t)dt \int_{4}^{6} r(t) d t \newline(B) r(6) r(6) \newline(C) 06r(t)dt \int_{0}^{6} r(t) d t \newline(D) 80+46r(t)dt 80+\int_{4}^{6} r(t) d t

Full solution

Q. Consider the following problem:\newlineThe number of people in Bernardo's social network is increasing at a rate of r(t)=2(t3)2+23 r(t)=-2(t-3)^{2}+23 people per month (where t t is the time in months since Bernardo set up the network). At time t=4 t=4 months, Bernardo had 8080 people in his social network. How many people were in Bernardo's social network at the end of the 6th  6^{\text {th }} month?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) 46r(t)dt \int_{4}^{6} r(t) d t \newline(B) r(6) r(6) \newline(C) 06r(t)dt \int_{0}^{6} r(t) d t \newline(D) 80+46r(t)dt 80+\int_{4}^{6} r(t) d t
  1. Calculate Change in People: To find the number of people in Bernardo's social network at the end of the 6th6^{\text{th}} month, we need to calculate the change in the number of people from the 4th4^{\text{th}} month to the 6th6^{\text{th}} month and add it to the number of people he had at the 4th4^{\text{th}} month. The rate of change of the number of people in his network is given by the function r(t)=2(t3)2+23r(t) = -2(t-3)^2 + 23. We need to integrate this rate function from t=4t=4 to t=6t=6 to find the total change in the number of people during this time period.
  2. Rate Function Integration: The correct expression to calculate the total change in the number of people from the 4th4^{\text{th}} month to the 6th6^{\text{th}} month is the definite integral of r(t)r(t) from t=4t=4 to t=6t=6. This is because integration of the rate function over a time interval gives us the net change in the quantity over that interval.
  3. Total Change Calculation: The expression that represents the total change in the number of people from the 4th4^{\text{th}} month to the 6th6^{\text{th}} month is therefore 46r(t)dt\int_{4}^{6} r(t) \, dt. This corresponds to choice (A) 46r(t)dt\int_{4}^{6}r(t)\,dt.
  4. Final Number of People Calculation: To find the total number of people in the network at the end of the 6th6^{\text{th}} month, we need to add the result of the integral to the number of people Bernardo had at the 4th4^{\text{th}} month, which is 8080. So the correct expression to find the total number of people at the end of the 6th6^{\text{th}} month is 80+46r(t)dt80 + \int_{4}^{6} r(t) \, dt. This corresponds to choice (D) 80+46r(t)dt80+\int_{4}^{6}r(t)\,dt.

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