Condense the logarithm 7log a-x log d Answer: log(◻)

Rewrite using power rule: We are given the expression 7log(a) - xlog(d) and we need to condense it into a single logarithm. According to the properties of logarithms, specifically the power rule which states that n*log_b(m) = log_b(m^n), we can rewrite each term as follows: 7log(a) becomes log(a^7) and xlog(d) becomes log(d^x).Combine using quotient rule: Now we have log(a^7) - log(d^x). According to the quotient rule of logarithms, which states that log_b(m) - log_b(n) = log_b(m/n), we can combine these two logarithms into a single logarithm with a quotient inside. So, log(a^7) - log(d^x) becomes log(a^7/d^x).Final condensed expression: We have successfully condensed the original expression into a single logarithm. The final answer is log(a^7/d^x).

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Condense the logarithm

7log a-x log d
Answer:
log(◻)

Condense the logarithm $\newline$ $7 \log a-x \log d$ $\newline$ Answer: $\log (\square)$

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Precalculus

Convert between exponential and logarithmic form

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Q. Condense the logarithm

\newline

7 \log a-x \log d

\newline

Answer:

\log (\square)

Rewrite using power rule: We are given the expression $7\log(a) - x\log(d)$ and we need to condense it into a single logarithm. $\newline$ According to the properties of logarithms, specifically the power rule which states that $n\log_b(m) = \log_b(m^n)$ , we can rewrite each term as follows: $\newline$ $7\log(a)$ becomes $\log(a^7)$ and $x\log(d)$ becomes $\log(d^x)$ .
Combine using quotient rule: Now we have $\log(a^7) - \log(d^x)$ . According to the quotient rule of logarithms, which states that $\log_b(m) - \log_b(n) = \log_b\left(\frac{m}{n}\right)$ , we can combine these two logarithms into a single logarithm with a quotient inside. $\newline$ So, $\log(a^7) - \log(d^x)$ becomes $\log\left(\frac{a^7}{d^x}\right)$ .
Final condensed expression: We have successfully condensed the original expression into a single logarithm. The final answer is $\log\left(\frac{a^7}{d^x}\right)$ .