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Complete the square to re-write the quadratic function in vertex form:

y=x^(2)-9x-3
Answer: 
y=

Complete the square to re-write the quadratic function in vertex form:\newliney=x29x3 y=x^{2}-9 x-3 \newlineAnswer: y= y=

Full solution

Q. Complete the square to re-write the quadratic function in vertex form:\newliney=x29x3 y=x^{2}-9 x-3 \newlineAnswer: y= y=
  1. Focus on x-terms: To complete the square, we first need to focus on the x-terms in the quadratic function. The function is y=x29x3y = x^2 - 9x - 3. We want to form a perfect square trinomial with the x-terms. To do this, we take the coefficient of the x-term, which is 9-9, divide it by 22, and then square the result.
  2. Form perfect square trinomial: Dividing the coefficient of xx, which is 9-9, by 22 gives us 4.5-4.5. Squaring 4.5-4.5 gives us 20.2520.25. This is the number we will add and subtract inside the parentheses to complete the square.
  3. Rewrite function with addition and subtraction: We rewrite the function by adding and subtracting 20.2520.25 inside the parentheses: y=(x29x+20.25)20.253y = (x^2 - 9x + 20.25) - 20.25 - 3. We have added 20.2520.25 to complete the square and subtracted it immediately to keep the equation balanced.
  4. Factor perfect square trinomial: Now we can factor the perfect square trinomial inside the parentheses: y=(x4.5)220.253y = (x - 4.5)^2 - 20.25 - 3.
  5. Combine constants: Next, we combine the constants outside the parentheses: 20.253=23.25-20.25 - 3 = -23.25. So the function becomes y=(x4.5)223.25y = (x - 4.5)^2 - 23.25.
  6. Quadratic function in vertex form: We have now completed the square, and the quadratic function is in vertex form. The vertex form of the function is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola. In our case, a=1a = 1, h=4.5h = 4.5, and k=23.25k = -23.25.

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