Complete the recursive formula of the arithmetic sequence 4,22,40,58,dots. {:[b(1)=◻],[b(n)=b(n-1)+]:}

Find First Term: To find the first term of the arithmetic sequence, we look at the first given term in the sequence. The first term is 4.Find Common Difference: To find the common difference, we subtract the first term from the second term. Common difference (d) = 22 - 4 = 18.Check Consistency: We check if the common difference is consistent by subtracting subsequent terms. 40 - 22 should also equal 18, and 58 - 40 should also equal 18. Let's check: 40 - 22 = 18 and 58 - 40 = 18. The common difference is consistent.Write Recursive Formula: Now we can write the recursive formula for the arithmetic sequence. The first term is b(1) = 4. The recursive formula is b(n) = b(n-1) + 18 for n > 1.

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Complete the recursive formula of the arithmetic sequence $\newline$ $4, 22, 40, 58, \dots$ . $\newline$ $b(1)=\square$ $\newline$ $b(n) = b(n-1) +\square$

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Q. Complete the recursive formula of the arithmetic sequence

\newline

4, 22, 40, 58, \dots

\newline

b(1)=\square

\newline

b(n) = b(n-1) +\square

Find First Term: To find the first term of the arithmetic sequence, we look at the first given term in the sequence. $\newline$ The first term is $4$ .
Find Common Difference: To find the common difference, we subtract the first term from the second term. $\newline$ Common difference $d$ = $22 - 4 = 18$ .
Check Consistency: We check if the common difference is consistent by subtracting subsequent terms. $\newline$ $40 - 22$ should also equal $18$ , and $58 - 40$ should also equal $18$ . $\newline$ Let's check: $\newline$ $40 - 22 = 18$ and $58 - 40 = 18$ . $\newline$ The common difference is consistent.
Write Recursive Formula: Now we can write the recursive formula for the arithmetic sequence. $\newline$ The first term is $b(1) = 4$ . $\newline$ The recursive formula is $b(n) = b(n-1) + 18$ for n > 1.