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Complete the point-slope equation of the line through 
(-9,6) and 
(-7,-8).
Use exact numbers.

y-6=

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Complete the point-slope equation of the line through (9,6) (-9,6) and (7,8) (-7,-8) .\newlineUse exact numbers.\newliney6= y-6= \newline \square

Full solution

Q. Complete the point-slope equation of the line through (9,6) (-9,6) and (7,8) (-7,-8) .\newlineUse exact numbers.\newliney6= y-6= \newline \square
  1. Calculate the Slope: To find the point-slope form of the equation of the line, we first need to calculate the slope of the line using the two given points (9,6)(-9, 6) and (7,8)(-7, -8). The slope mm is given by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points.\newlineLet's calculate the slope:\newlinem=867(9)m = \frac{-8 - 6}{-7 - (-9)}\newlinem=142m = \frac{-14}{2}\newlinem=7m = -7
  2. Write Point-Slope Form: Now that we have the slope, we can use one of the points and the slope to write the point-slope form of the equation. The point-slope form is given by yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line.\newlineLet's use the point (9,6)(-9, 6) and the slope 7-7 to write the equation:\newliney6=7(x(9))y - 6 = -7(x - (-9))\newliney6=7(x+9)y - 6 = -7(x + 9)

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