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Complete the point-slope equation of the line through (-5,4) and (1,6).
Use exact numbers.
y-6=◻

Complete the point-slope equation of the line through (5,4) (-5,4) and (1,6) (1,6) .\newlineUse exact numbers.\newliney6=y-6= \square \newline

Full solution

Q. Complete the point-slope equation of the line through (5,4) (-5,4) and (1,6) (1,6) .\newlineUse exact numbers.\newliney6=y-6= \square \newline
  1. Calculate Slope: To find the point-slope form of the equation of a line, we first need to calculate the slope of the line using the two given points (5,4)(-5,4) and (1,6)(1,6). The slope mm is given by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points.
  2. Substitute Coordinates: Substitute the coordinates of the points into the slope formula: m=641(5)=21+5=26=13m = \frac{6 - 4}{1 - (-5)} = \frac{2}{1 + 5} = \frac{2}{6} = \frac{1}{3}.
  3. Write Point-Slope Form: Now that we have the slope, we can use one of the points and the slope to write the point-slope form of the equation. The point-slope form is yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line. We can use either of the two points, but let's use the point (1,6)(1,6) for this example.
  4. Substitute Slope and Point: Substitute the slope and the coordinates of the point (1,6)(1,6) into the point-slope form: y6=13(x1)y - 6 = \frac{1}{3}(x - 1).

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