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Chloe has a collection of vintage action figures that is worth 
$310. If the collection appreciates at a rate of 
15% per year, which equation represents the value of the collection after 5 years?

V=310(1.15)^(5)

V=310(1+0.15)

V=310(1-0.15)^(5)

V=310(0.85)^(5)

Chloe has a collection of vintage action figures that is worth $310 \$ 310 . If the collection appreciates at a rate of 15% 15 \% per year, which equation represents the value of the collection after 55 years?\newlineV=310(1.15)5 V=310(1.15)^{5} \newlineV=310(1+0.15) V=310(1+0.15) \newlineV=310(10.15)5 V=310(1-0.15)^{5} \newlineV=310(0.85)5 V=310(0.85)^{5}

Full solution

Q. Chloe has a collection of vintage action figures that is worth $310 \$ 310 . If the collection appreciates at a rate of 15% 15 \% per year, which equation represents the value of the collection after 55 years?\newlineV=310(1.15)5 V=310(1.15)^{5} \newlineV=310(1+0.15) V=310(1+0.15) \newlineV=310(10.15)5 V=310(1-0.15)^{5} \newlineV=310(0.85)5 V=310(0.85)^{5}
  1. Question Prompt: Question prompt: Which equation represents the value of Chloe's vintage action figure collection after 55 years, given a 15%15\% annual appreciation rate?
  2. Identify Values: Identify the initial value aa and the growth rate rr. The initial value of the collection is $310\$310, and the annual appreciation rate is 15%15\%, which can be expressed as a decimal 0.150.15.
  3. Convert Rate to Factor: Convert the appreciation rate to a growth factor (bb).\newlineThe growth factor is found by adding 11 to the appreciation rate expressed as a decimal.\newlineb=1+rb = 1 + r\newlineb=1+0.15b = 1 + 0.15\newlineb=1.15b = 1.15
  4. Write Exponential Equation: Write the exponential growth equation using the initial value and the growth factor.\newlineThe general form of the exponential growth equation is V=a(b)tV = a(b)^t, where VV is the final value, aa is the initial value, bb is the growth factor, and tt is the time in years.\newlineSubstitute $310\$310 for 'a', 1.151.15 for 'b', and 55 for 't'.\newlineV=310(1.15)5V = 310(1.15)^5

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