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Chee is organizing textbooks on her bookshelf. She has a Spanish textbook, a math textbook, and a physics textbook. How many different ways can she line the textbooks up on her bookshelf?
Answer:

Chee is organizing textbooks on her bookshelf. She has a Spanish textbook, a math textbook, and a physics textbook. How many different ways can she line the textbooks up on her bookshelf? $\newline$ Answer:

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Compound events: find the number of outcomes

Full solution

Q. Chee is organizing textbooks on her bookshelf. She has a Spanish textbook, a math textbook, and a physics textbook. How many different ways can she line the textbooks up on her bookshelf?

\newline

Answer:

Permutations of Textbooks: To determine the number of different ways Chee can line up her textbooks, we need to consider the permutations of the three books. A permutation is an arrangement of all the members of a set in some sequence or order. Since the order matters, we will use the formula for permutations without repetition, which is $n!$ ( $n$ factorial), where $n$ is the number of items to arrange.
Calculate Factorial: Chee has $3$ textbooks to arrange. Therefore, $n = 3$ . We need to calculate $3!$ ( $3$ factorial), which is the product of all positive integers up to $3$ . $\newline$ $3! = 3 \times 2 \times 1 = 6$
Total Number of Ways: We have calculated that there are $6$ different ways Chee can line up her three textbooks on her bookshelf.

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