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c(n)=−6+5(n−1)c(n) = -6 + 5(n - 1) \newlineFind the 8th8^{\text{th}} term in the sequence. \newline□\square

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Q. c(n)=−6+5(n−1)c(n) = -6 + 5(n - 1) \newlineFind the 8th8^{\text{th}} term in the sequence. \newline□\square
  1. Identify Formula: Identify the formula for the nnth term of the sequence.\newlineThe given formula is c(n)=−6+5(n−1)c(n) = -6 + 5(n - 1). This formula allows us to find the value of any term in the sequence by substituting the term's position (nn) into the formula.
  2. Substitute Term Number: Substitute the term number into the formula to find the 8th8^{\text{th}} term.\newlineWe want to find c(8)c(8), which means we substitute n=8n = 8 into the formula.\newlinec(8)=−6+5(8−1)c(8) = -6 + 5(8 - 1)
  3. Perform Calculation: Perform the calculation inside the parentheses first, according to the order of operations (PEMDAS/BODMAS). c(8)=−6+5(7)c(8) = -6 + 5(7)
  4. Multiply Result: Multiply 55 by the result from the previous step.\newlinec(8)=−6+5×7c(8) = -6 + 5 \times 7\newlinec(8)=−6+35c(8) = -6 + 35
  5. Add to Find Term: Add −6-6 to the result of the multiplication to find the 88th term.\newlinec(8)=35−6c(8) = 35 - 6\newlinec(8)=29c(8) = 29

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