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c(n)=(4)/(9)(-3)^(n-1)
What is the 
3^("rd ") term in the sequence?

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c(n)=49(3)n1c(n)=\frac{4}{9}(-3)^{n-1}\newlineWhat is the 3rd  3^{\text {rd }} term in the sequence?\newline \square

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