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$$\left\{\begin{array}{l} \frac{2}{y-7 x}-\frac{3}{x+3 y}=12 \\ \frac{9}{y-7 x}-\frac{1}{x+3 y}=17 \end{array}\right.$$$\newline$Which of the following substitutions will make both equations linear?$\newline$Choose $1$ answer:$\newline$(A) $p=\frac{1}{y-7 x}$ and $q=\frac{1}{x+3 y}$$\newline$(B) $p=y-7 x$ and $q=x+3 y$$\newline$(c) $p=\frac{1}{7 x}$ and $q=\frac{1}{3 y}$$\newline$(D) No substitution will work here.