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Evaluate: log_(4)(8-x)=log_(4)(6)

Evaluate: log⁡4(8−x)=log⁡4(6)\log_{4}(8-x)=\log_{4}(6)

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Full solution

Q. Evaluate: log⁡4(8−x)=log⁡4(6)\log_{4}(8-x)=\log_{4}(6)
  1. Set Logarithms Equal: Step 11: Set the arguments of the logarithms equal to each other since their bases are the same and the logs are equal.\newline8−x=68 - x = 6
  2. Solve for x: Step 22: Solve for x by subtracting 88 from both sides.\newline8−x−8=6−88 - x - 8 = 6 - 8\newlinex=2x = 2

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