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Bilquis is younger than Mav. Their ages are consecutive even integers. Find Bilquis's age if the sum of Bilquis's age and 2 times Mav's age is
82.
Answer:

Bilquis is younger than Mav. Their ages are consecutive even integers. Find Bilquis's age if the sum of Bilquis's age and $2$ times Mav's age is ${8 2}$ . $\newline$ Answer:

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Experimental probability

Full solution

Q. Bilquis is younger than Mav. Their ages are consecutive even integers. Find Bilquis's age if the sum of Bilquis's age and

2

times Mav's age is

{8 2}

.

\newline

Answer:

Set Up Equations: Let's denote Bilquis's age as $B$ and Mav's age as $M$ . Since their ages are consecutive even integers, we can express Mav's age as $B + 2$ . The problem states that the sum of Bilquis's age and $2$ times Mav's age is $82$ . We can write this as an equation: $B + 2 \times (B + 2) = 82$
Simplify and Solve: Now, let's simplify and solve the equation: $B + 2B + 4 = 82$ $3B + 4 = 82$
Isolate Terms with B: Subtract $4$ from both sides of the equation to isolate the terms with $B$ : $\newline$ $3B + 4 - 4 = 82 - 4$ $\newline$ $3B = 78$
Solve for B: Divide both sides of the equation by $3$ to solve for B: $\newline$ $\frac{3B}{3} = \frac{78}{3}$ $\newline$ $B = 26$
Check Solution: Now that we have Bilquis's age, we should check if it is an even integer, as the problem states that their ages are consecutive even integers. $26$ is an even number, so our solution is consistent with the problem's conditions.

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