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Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest 1ooth if necessary.

{:[" 1-Var-Stats "],[ bar(x)=106],[Sigma x=742],[Sigmax^(2)=80706],[Sx=18.5022521152],[sigma x=17.1297568993],[n=7],[minX=81],[Q_(1)=87],[Med^(2)=113],[Q_(3)=121],[maxX=126]:}
Answer:

Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest 11ooth if necessary.\newline 1-Var-Stats xˉ=106Σx=742Σx2=80706Sx=18.5022521152σx=17.1297568993n=7minX=81Q1=87Med2=113Q3=121maxX=126 \begin{array}{l} \text { 1-Var-Stats } \\ \bar{x}=106 \\ \Sigma x=742 \\ \Sigma x^{2}=80706 \\ S x=18.5022521152 \\ \sigma x=17.1297568993 \\ n=7 \\ \operatorname{minX}=81 \\ \mathrm{Q}_{1}=87 \\ \mathrm{Med}^{2}=113 \\ \mathrm{Q}_{3}=121 \\ \max \mathrm{X}=126 \end{array} \newlineAnswer:

Full solution

Q. Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest 11ooth if necessary.\newline 1-Var-Stats xˉ=106Σx=742Σx2=80706Sx=18.5022521152σx=17.1297568993n=7minX=81Q1=87Med2=113Q3=121maxX=126 \begin{array}{l} \text { 1-Var-Stats } \\ \bar{x}=106 \\ \Sigma x=742 \\ \Sigma x^{2}=80706 \\ S x=18.5022521152 \\ \sigma x=17.1297568993 \\ n=7 \\ \operatorname{minX}=81 \\ \mathrm{Q}_{1}=87 \\ \mathrm{Med}^{2}=113 \\ \mathrm{Q}_{3}=121 \\ \max \mathrm{X}=126 \end{array} \newlineAnswer:
  1. Identify symbol for population standard deviation: Identify the symbol for population standard deviation in the calculator output.\newlineThe symbol for population standard deviation is σx\sigma_x in the given output.
  2. Locate value in calculator output: Locate the value of the population standard deviation in the calculator output.\newlineThe value given for "sigma x" is 17.129756899317.1297568993.
  3. Round to nearest hundredth: Round the population standard deviation to the nearest hundredth.\newlineRounding 17.129756899317.1297568993 to the nearest hundredth gives us 17.1317.13.