Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest 1ooth if necessary.

{:[" 1-Var-Stats "],[ bar(x)=270],[Sigma x=1890],[Sigmax^(2)=512150],[Sx=17.5594229214],[sigma x=16.2568666811],[n=7],[minX=240],[Q_(1)=257],[Med^(2)=274],[Q_(3)=282],[maxX=291]:}
Answer:

Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest 11ooth if necessary.\newline 1-Var-Stats xˉ=270Σx=1890Σx2=512150Sx=17.5594229214σx=16.2568666811n=7minX=240Q1=257Med2=274Q3=282maxX=291 \begin{array}{l} \text { 1-Var-Stats } \\ \bar{x}=270 \\ \Sigma x=1890 \\ \Sigma x^{2}=512150 \\ S x=17.5594229214 \\ \sigma x=16.2568666811 \\ n=7 \\ \operatorname{minX}=240 \\ \mathrm{Q}_{1}=257 \\ \mathrm{Med}^{2}=274 \\ \mathrm{Q}_{3}=282 \\ \max \mathrm{X}=291 \end{array} \newlineAnswer:

Full solution

Q. Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest 11ooth if necessary.\newline 1-Var-Stats xˉ=270Σx=1890Σx2=512150Sx=17.5594229214σx=16.2568666811n=7minX=240Q1=257Med2=274Q3=282maxX=291 \begin{array}{l} \text { 1-Var-Stats } \\ \bar{x}=270 \\ \Sigma x=1890 \\ \Sigma x^{2}=512150 \\ S x=17.5594229214 \\ \sigma x=16.2568666811 \\ n=7 \\ \operatorname{minX}=240 \\ \mathrm{Q}_{1}=257 \\ \mathrm{Med}^{2}=274 \\ \mathrm{Q}_{3}=282 \\ \max \mathrm{X}=291 \end{array} \newlineAnswer:
  1. Identify symbol for population standard deviation: Identify the symbol for population standard deviation in the calculator output.\newlineThe symbol for population standard deviation in the calculator output is "σx\sigma_x". This is the value we are looking for.
  2. Locate value in calculator output: Locate the value of the population standard deviation in the calculator output.\newlineThe value given for "sigma x" in the output is 16.256866681116.2568666811.
  3. Round to nearest hundredth: Round the population standard deviation to the nearest hundredth.\newlineTo round to the nearest hundredth, we look at the third decimal place. If it is 55 or more, we round up. If it is less than 55, we round down. The third decimal place of 16.256866681116.2568666811 is 66, so we round up the second decimal place from 55 to 66.\newlineThe rounded population standard deviation is 16.2616.26.