b) lim_(x rarr+oo)(sqrt(4x^(2)-3x+7)-x)/(x+2) (1pt)

Simplify Inside Square Root: Simplify the expression inside the square root for large x values. As x approaches infinity, the term -3x becomes negligible compared to 4x^2, so we approximate sqrt(4x^2 - 3x + 7) ≈ sqrt(4x^2).Simplify Square Root: Simplify the square root. sqrt(4x^2) = 2x, because the square root and square cancel out, and we take the positive root since x is approaching infinity.Substitute Back: Substitute back into the original limit expression. Replace sqrt(4x^2 - 3x + 7) with 2x in the limit expression: (2x - x) / (x + 2).Simplify Numerator: Simplify the numerator. 2x - x = x.Simplify Entire Expression: Simplify the entire expression. (x) / (x + 2) = 1 / (1 + 2/x).Evaluate Limit: Evaluate the limit as x approaches infinity. As x approaches infinity, 2/x approaches 0, so 1 + 2/x approaches 1. Therefore, the limit of 1 / (1 + 2/x) as x approaches infinity is 1.

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Algebra 1

Add and subtract polynomials

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\lim _{x \rightarrow+\infty} \frac{\sqrt{4 x^{2}-3 x+7}-x}{x+2}

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Simplify Inside Square Root: Simplify the expression inside the square root for large $x$ values. $\newline$ As $x$ approaches infinity, the term $-3x$ becomes negligible compared to $4x^2$ , so we approximate $\sqrt{4x^2 - 3x + 7} \approx \sqrt{4x^2}$ .
Simplify Square Root: Simplify the square root. $\sqrt{4x^2} = 2x$ , because the square root and square cancel out, and we take the positive root since $x$ is approaching infinity.
Substitute Back: Substitute back into the original limit expression. $\newline$ Replace $\sqrt{4x^2 - 3x + 7}$ with $2x$ in the limit expression: $\frac{2x - x}{x + 2}$ .
Simplify Numerator: Simplify the numerator. $2x - x = x$ .
Simplify Entire Expression: Simplify the entire expression. $\newline$ $\frac{x}{x + 2} = \frac{1}{1 + \frac{2}{x}}$ .
Evaluate Limit: Evaluate the limit as $x$ approaches infinity. $\newline$ As $x$ approaches infinity, $\frac{2}{x}$ approaches $0$ , so $1 + \frac{2}{x}$ approaches $1$ . Therefore, the limit of $\frac{1}{1 + \frac{2}{x}}$ as $x$ approaches infinity is $1$ .