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b3×(b4)2=bxb^3 \times (b^4)^2 = b^x \newline x=x=\square

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Q. b3×(b4)2=bxb^3 \times (b^4)^2 = b^x \newline x=x=\square
  1. Understand the problem: Understand the problem and the properties of exponents. We need to find the value of xx in the expression b3(b4)2=bxb^3 \cdot (b^4)^2 = b^x. According to the properties of exponents, when we multiply two exponents with the same base, we add the exponents. Also, when we raise an exponent to another power, we multiply the exponents.
  2. Apply power property: Apply the power of a power property to (b4)2(b^4)^2.(b4)2(b^4)^2 means that we multiply the exponent 44 by 22.(b4)2=b(42)=b8(b^4)^2 = b^{(4*2)} = b^8
  3. Multiply exponents: Multiply b3b^3 by b8b^8 using the property of exponents for multiplication.\newlineNow we multiply b3b^3 by b8b^8, which means we add the exponents.\newlineb3×b8=b3+8=b11b^3 \times b^8 = b^{3+8} = b^{11}
  4. Solve for x: Set the result equal to bxb^x and solve for xx.\newlineWe have b3(b4)2=b11b^3 \cdot (b^4)^2 = b^{11}, and this is set equal to bxb^x.\newlineTherefore, bx=b11b^x = b^{11}\newlineSo, x=11x = 11

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