Find the missing coordinate to complete the ordered-pair solution to the given linear equation $\newline$ $5x-4y=27$ $\newline$ $(-1,)$

Full solution

Q. Find the missing coordinate to complete the ordered-pair solution to the given linear equation

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5x-4y=27

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(-1,)

Substitute and Solve for y: To find the missing y-coordinate for the point $(-1, ?)$ , substitute $x = -1$ into the equation $5x - 4y = 27$ and solve for y. $\newline$ $5(-1) - 4y = 27$ $\newline$ $-5 - 4y = 27$
Addition to Isolate y: Now, add $5$ to both sides of the equation to isolate the term with $y$ . $\newline$ $-5 + 5 - 4y = 27 + 5$ $\newline$ $-4y = 32$
Divide to Solve for y: Next, divide both sides by $-4$ to solve for y. $\newline$ $\frac{-4y}{-4} = \frac{32}{-4}$ $\newline$ $y = -8$
Substitute and Solve for x: For the point $(?, 2)$ , substitute $y = 2$ into the equation $5x - 4y = 27$ and solve for $x$ . $\newline$ $5x - 4(2) = 27$ $\newline$ $5x - 8 = 27$
Addition to Isolate x: Add $8$ to both sides of the equation to isolate the term with $x$ . $\newline$ $5x - 8 + 8 = 27 + 8$ $\newline$ $5x = 35$
Divide to Solve for x: Finally, divide both sides by $5$ to solve for x. $\newline$ $\frac{5x}{5} = \frac{35}{5}$ $\newline$ $x = 7$