At a lunch stand, each hamburger has 50 more calories than each order of fries. If 2 hamburgers and 3 orders of fries have a total of 1700 calories, how many calories does a hamburger have?
Q. At a lunch stand, each hamburger has 50 more calories than each order of fries. If 2 hamburgers and 3 orders of fries have a total of 1700 calories, how many calories does a hamburger have?
Define Variables: Let's denote the number of calories in a hamburger as H and the number of calories in an order of fries as F. According to the problem, a hamburger has 50 more calories than an order of fries, so we can write this relationship as:H=F+50
Total Calories Equation: We also know that 2 hamburgers and 3 orders of fries have a total of 1700 calories. We can express this information as an equation:2H+3F=1700
Substitute for H: Now we can substitute the expression for H from the first step into the second equation to find the value of F:2(F+50)+3F=1700
Combine Like Terms: Let's distribute the 2 into the parentheses and combine like terms: 2F+100+3F=17005F+100=1700
Isolate F: Now, we will subtract 100 from both sides to isolate the term with F: 5F+100−100=1700−1005F=1600
Solve for F: Next, we divide both sides by 5 to solve for F:55F=51600F=320
Find Calories in H: Now that we have the value for F, we can find the number of calories in a hamburger by going back to the first equation and substituting the value of F:H=F+50H=320+50H=370
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