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At a lunch stand, each hamburger has 5050 more calories than each order of fries. If 22 hamburgers and 33 orders of fries have a total of 17001700 calories, how many calories does a hamburger have?

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Q. At a lunch stand, each hamburger has 5050 more calories than each order of fries. If 22 hamburgers and 33 orders of fries have a total of 17001700 calories, how many calories does a hamburger have?
  1. Define Variables: Let's denote the number of calories in a hamburger as HH and the number of calories in an order of fries as FF. According to the problem, a hamburger has 5050 more calories than an order of fries, so we can write this relationship as:\newlineH=F+50H = F + 50
  2. Total Calories Equation: We also know that 22 hamburgers and 33 orders of fries have a total of 17001700 calories. We can express this information as an equation:\newline2H+3F=17002H + 3F = 1700
  3. Substitute for H: Now we can substitute the expression for H from the first step into the second equation to find the value of F:\newline2(F+50)+3F=17002(F + 50) + 3F = 1700
  4. Combine Like Terms: Let's distribute the 22 into the parentheses and combine like terms: 2F+100+3F=17002F + 100 + 3F = 1700 5F+100=17005F + 100 = 1700
  5. Isolate F: Now, we will subtract 100100 from both sides to isolate the term with FF: \newline5F+100100=17001005F + 100 - 100 = 1700 - 100\newline5F=16005F = 1600
  6. Solve for F: Next, we divide both sides by 55 to solve for F:\newline5F5=16005\frac{5F}{5} = \frac{1600}{5}\newlineF=320F = 320
  7. Find Calories in H: Now that we have the value for F, we can find the number of calories in a hamburger by going back to the first equation and substituting the value of F:\newlineH=F+50H = F + 50\newlineH=320+50H = 320 + 50\newlineH=370H = 370

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Posted 8 months ago