At a back-to-school sale at her favorite store, Karen can purchase any pair of pants for $17 and any shirt for $10. Her parents tell her that she can spend at most $360 on these school clothes.Select the inequality in standard form that describes this situation. Use the given numbers and the following variables.x= the number of pairs of pantsy= the number of shirtsChoices:(A) 17x×10y≤360(B) 17x+10y≤360(C) 17x+10y≥360(D) 17x×10y≥360
Q. At a back-to-school sale at her favorite store, Karen can purchase any pair of pants for $17 and any shirt for $10. Her parents tell her that she can spend at most $360 on these school clothes.Select the inequality in standard form that describes this situation. Use the given numbers and the following variables.x= the number of pairs of pantsy= the number of shirtsChoices:(A) 17x×10y≤360(B) 17x+10y≤360(C) 17x+10y≥360(D) 17x×10y≥360
Calculate Costs: Determine the cost for one pair of pants and one shirt. Karen can buy pants for $17 each and shirts for $10 each. The variables given are x for the number of pairs of pants and y for the number of shirts. Therefore, the cost for x pairs of pants is 17x dollars and the cost for y shirts is 10y dollars.
Find Total Cost: Combine the costs to find the total cost. The total amount Karen can spend is the sum of the cost of pants and the cost of shirts, which is 17x+10y dollars.
Apply Budget Constraint: Apply the budget constraint. Karen's parents have told her that she can spend at most $360 on school clothes. This means the total cost of pants and shirts must be less than or equal to$360. Therefore, the inequality that represents this situation is 17x+10y≤360.
Match Inequality: Match the inequality to the given choices. The correct inequality that represents Karen's situation is 17x+10y≤360, which corresponds to choice (B).
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