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Answer:
(b) 
((h-1))/(2)+((h-2))/(3)=3

Answer:\newline(b) (h1)2+(h2)3=3 \frac{(h-1)}{2}+\frac{(h-2)}{3}=3

Full solution

Q. Answer:\newline(b) (h1)2+(h2)3=3 \frac{(h-1)}{2}+\frac{(h-2)}{3}=3
  1. Find Common Denominator: Find a common denominator for the fractions on the left side of the equation.\newlineThe common denominator for 22 and 33 is 66.
  2. Rewrite Fractions: Rewrite each fraction with the common denominator.\newlineh12×33+h23×22=3\frac{h-1}{2} \times \frac{3}{3} + \frac{h-2}{3} \times \frac{2}{2} = 3\newlineThis becomes 3(h1)6+2(h2)6=3\frac{3(h-1)}{6} + \frac{2(h-2)}{6} = 3
  3. Combine Fractions: Combine the fractions on the left side since they have the same denominator. 3(h1)+2(h2)6=3\frac{3(h-1) + 2(h-2)}{6} = 3
  4. Distribute and Combine: Distribute the numerators and combine like terms. \newline(3h3+2h4)/6=3(3h - 3 + 2h - 4)/6 = 3\newlineThis simplifies to (5h7)/6=3(5h - 7)/6 = 3
  5. Eliminate Denominator: Multiply both sides of the equation by 66 to eliminate the denominator.\newline(5h7)/6×6=3×6(5h - 7)/6 \times 6 = 3 \times 6\newlineThis simplifies to 5h7=185h - 7 = 18
  6. Isolate h Term: Add 77 to both sides of the equation to isolate the term with hh. \newline5h7+7=18+75h - 7 + 7 = 18 + 7\newlineThis simplifies to 5h=255h = 25
  7. Solve for hh: Divide both sides by 55 to solve for hh.5h5=255\frac{5h}{5} = \frac{25}{5}This simplifies to h=5h = 5

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