Ann increased the quantities of all the ingredients in a recipe by 60%. She used 80 grams (g) of cheese. How much cheese did the recipe require? g

Understand the problem: Understand the problem. Ann increased the amount of cheese by 60%. She used 80 grams after the increase. We need to find out how much cheese the original recipe required before the increase.Express the increase: Express the increase in terms of the original amount. Let the original amount of cheese be x grams. The increase of 60% on the original amount can be expressed as 0.60 * x.Write the equation: Write the equation that represents the total amount of cheese after the increase. The total amount of cheese after the increase is the original amount plus the increase, which is x + 0.60 * x.Set up the equation: We know that the total amount after the increase is 80 grams, so we can set up the equation: x + 0.60 * x = 80Combine like terms: Combine like terms to simplify the equation. 1x + 0.60x = 1.60x So, 1.60x = 80Divide to solve: Divide both sides of the equation by 1.60 to solve for x. x = 80 / 1.60Calculate value: Calculate the value of x. x = 50

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Ann increased the quantities of all the ingredients in a recipe by
60%. She used 80 grams
(g) of cheese.
How much cheese did the recipe require?

g

Ann increased the quantities of all the ingredients in a recipe by $60 \%$ . She used $80$ grams $(\mathrm{g})$ of cheese. $\newline$ How much cheese did the recipe require? $\newline$ g

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Q. Ann increased the quantities of all the ingredients in a recipe by

60 \%

. She used

80

grams

(\mathrm{g})

of cheese.

\newline

How much cheese did the recipe require?

\newline

Understand the problem: Understand the problem. $\newline$ Ann increased the amount of cheese by $60\%$ . She used $80$ grams after the increase. We need to find out how much cheese the original recipe required before the increase.
Express the increase: Express the increase in terms of the original amount. $\newline$ Let the original amount of cheese be $x$ grams. The increase of $60\%$ on the original amount can be expressed as $0.60 \times x$ .
Write the equation: Write the equation that represents the total amount of cheese after the increase. $\newline$ The total amount of cheese after the increase is the original amount plus the increase, which is $x + 0.60 \times x$ .
Set up the equation: We know that the total amount after the increase is $80$ grams, so we can set up the equation: $\newline$ $x + 0.60 \times x = 80$
Combine like terms: Combine like terms to simplify the equation. $\newline$ $1x + 0.60x = 1.60x$ $\newline$ So, $1.60x = 80$
Divide to solve: Divide both sides of the equation by $1.60$ to solve for $x$ . $\newline$ $x = \frac{80}{1.60}$
Calculate value: Calculate the value of $x$ . $x = 50$