An empty pool has the capacity to hold 2700 cubic feet (ft^(3)) of water. A particular hose fills this pool with water at a rate of 25ft^(3) per minute. If the hose is placed into the empty pool and turned on, approximately what percent of the pool will be filled with water after 1 hour? Choose 1 answer: (A) 10% (B) 44% (C) 56% (D) 93%

Calculate total water amount: Calculate the total amount of water that the hose will fill in 1 hour. Since there are 60 minutes in an hour, the hose will fill 25 ft^3/minute * 60 minutes = 1500 ft^3 in one hour.Calculate percentage filled: Calculate the percentage of the pool that will be filled with water after 1 hour. The pool's total capacity is 2700 ft^3. The hose fills 1500 ft^3 in one hour. To find the percentage filled, divide the amount filled by the total capacity and multiply by 100. Percentage filled = (1500 ft^3 / 2700 ft^3) * 100Perform calculation: Perform the calculation to find the percentage. Percentage filled = (1500 / 2700) * 100 Percentage filled = (5 / 9) * 100 Percentage filled ≈ 55.56%Choose closest answer: Choose the closest answer from the given options. The calculated percentage is approximately 55.56%, which is closest to option (C) 56%.

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An empty pool has the capacity to hold 2700 cubic feet
(ft^(3)) of water. A particular hose fills this pool with water at a rate of
25ft^(3) per minute. If the hose is placed into the empty pool and turned on, approximately what percent of the pool will be filled with water after 1 hour?
Choose 1 answer:
(A)
10%
(B)
44%
(C)
56%
(D)
93%

An empty pool has the capacity to hold $2700 \text{ cubic feet } (\text{ft}^{3})$ of water. A particular hose fills this pool with water at a rate of $25\text{ft}^{3} \text{ per minute}$ . If the hose is placed into the empty pool and turned on, approximately what percent of the pool will be filled with water after $1$ hour? $\newline$ Choose $1$ answer: $\newline$ (A) $10\%$ $\newline$ (B) $44\%$ $\newline$ (C) $56\%$ $\newline$ (D) $93\%$

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Q. An empty pool has the capacity to hold

2700 \text{ cubic feet } (\text{ft}^{3})

of water. A particular hose fills this pool with water at a rate of

25\text{ft}^{3} \text{ per minute}

. If the hose is placed into the empty pool and turned on, approximately what percent of the pool will be filled with water after

1

hour?

\newline

Choose

1

answer:

\newline

(A)

10\%

\newline

(B)

44\%

\newline

(C)

56\%

\newline

(D)

93\%

Calculate total water amount: Calculate the total amount of water that the hose will fill in $1$ hour. $\newline$ Since there are $60$ minutes in an hour, the hose will fill $25$ ft $^3$ /minute $*$ $60$ minutes = $1500$ ft $^3$ in one hour.
Calculate percentage filled: Calculate the percentage of the pool that will be filled with water after $1$ hour. $\newline$ The pool's total capacity is $2700 \, \text{ft}^3$ . The hose fills $1500 \, \text{ft}^3$ in one hour. To find the percentage filled, divide the amount filled by the total capacity and multiply by $100$ . $\newline$ Percentage filled = $(1500 \, \text{ft}^3 / 2700 \, \text{ft}^3) \times 100$
Perform calculation: Perform the calculation to find the percentage. $\newline$ Percentage filled = $(1500 / 2700) \times 100$ $\newline$ Percentage filled = $(5 / 9) \times 100$ $\newline$ Percentage filled $\approx 55.56\%$
Choose closest answer: Choose the closest answer from the given options. $\newline$ The calculated percentage is approximately $55.56\%$ , which is closest to option (C) $56\%$ .