An empty pool has the capacity to hold 2700 cubic feet (ft³) of water. A particular hose fills this pool with water at a rate of 25ft³ per minute. If the hose is placed into the empty pool and turned on, approximately what percent of the pool will be filled with water after 1 hour?

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Identify values: Identify the values given in the problem. The pool's capacity is 2700 ft³. The rate at which the hose fills the pool is 25 ft³ per minute. We need to find out how much of the pool is filled after 1 hour.Convert time: Convert the time from hours to minutes. Since the rate of the hose is given in minutes, we need to convert the time from hours to minutes. 1 hour = 60 minutesCalculate volume: Calculate the volume of water filled by the hose in 1 hour. Multiply the rate at which the hose fills the pool by the number of minutes in 1 hour. Volume filled in 1 hour = 25 ft³/minute * 60 minutes Volume filled in 1 hour = 1500 ft³Calculate percentage: Calculate the percentage of the pool that will be filled. Divide the volume filled in 1 hour by the total capacity of the pool and multiply by 100 to get the percentage. Percentage filled = (Volume filled in 1 hour / Pool's capacity) * 100 Percentage filled = (1500 ft³ / 2700 ft³) * 100Perform division: Perform the division and multiplication to find the percentage. Percentage filled = (1500 / 2700) * 100 Percentage filled = 0.5556 * 100 Percentage filled = 55.56%

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