Amy used her first 2 tokens at Glimmer Arcade to play a game of Roll-and-Score. Then she played her favorite game, Balloon Bouncer, over and over until she ran out of tokens. Balloon Bouncer costs 3 tokens per game, and Amy started with a bucket of 35 game tokens.Which equation can Amy use to find how many games of Balloon Bouncer, g, she played?Choices:(A) 3g+2=35(B) 2(g+3)=35(C) 3(g+2)=35(D) 2g+3=35How many games of Balloon Bouncer did Amy play?___ games
Q. Amy used her first 2 tokens at Glimmer Arcade to play a game of Roll-and-Score. Then she played her favorite game, Balloon Bouncer, over and over until she ran out of tokens. Balloon Bouncer costs 3 tokens per game, and Amy started with a bucket of 35 game tokens.Which equation can Amy use to find how many games of Balloon Bouncer, g, she played?Choices:(A) 3g+2=35(B) 2(g+3)=35(C) 3(g+2)=35(D) 2g+3=35How many games of Balloon Bouncer did Amy play?___ games
Understand the problem: Understand the problem.Amy used 2 tokens for the game of Roll-and-Score. She then played Balloon Bouncer, which costs 3 tokens per game, until she ran out of tokens. She had a total of 35 tokens. We need to find out how many games of Balloon Bouncer she played.
Translate the problem: Translate the problem into an equation.Amy used 2 tokens initially, so we subtract those from the total. For each game of Balloon Bouncer, she used 3 tokens. If g represents the number of games she played, then the cost for g games is 3g tokens. The equation representing the situation is the initial 2 tokens plus the cost of g games of Balloon Bouncer, which equals the total number of tokens Amy had.The equation is 3g+2=35.
Identify the correct equation: Identify the correct equation from the given choices.The correct equation that represents the situation is (A)3g+2=35.
Solve the equation: Solve the equation to find the number of games Amy played.We have the equation 3g+2=35. To solve for g, we first subtract 2 from both sides of the equation to isolate the term with g.3g+2−2=35−23g=33Next, we divide both sides by 3 to solve for g.33g=333g=11
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