Evaluate: 26-6root(3)(343)

Identify value in square root: Step 1: Identify the value inside the square root. Calculate √(343). 343 is 7^3, so √(343) = √(7^3) = 7√7.Multiply by 6: Step 2: Multiply the result by 6. Calculate 6 * 7√7. 6 * 7√7 = 42√7.Subtract from 26: Step 3: Subtract the result from 26. Calculate 26 - 42√7. This step involves subtracting a radical from a whole number, which cannot be simplified further.

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Evaluate: $\newline$ $26-6\sqrt[3]{343}$

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Math Problems

Algebra 2

Divide polynomials using long division

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Q. Evaluate:

\newline

26-6\sqrt[3]{343}

Identify value in square root: Step $1$ : Identify the value inside the square root. $\newline$ Calculate $\sqrt{343}$ . $\newline$ $343$ is $7^3$ , so $\sqrt{343}$ = $\sqrt{7^3}$ = $7\sqrt{7}$ .
Multiply by $6$ : Step $2$ : Multiply the result by $6$ . $\newline$ Calculate $6 \times 7\sqrt{7}$ . $\newline$ $6 \times 7\sqrt{7} = 42\sqrt{7}$ .
Subtract from $26$ : Step $3$ : Subtract the result from $26$ . $\newline$ Calculate $26 - 42\sqrt{7}$ . $\newline$ This step involves subtracting a radical from a whole number, which cannot be simplified further.