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After 2424 hours, 30%30\% of a 2525 milligram dose of a new antibiotic remains in the body. Which of the following functions, MM, models the amount of the antibiotic (in milligrams) that remains in the body after hh hours?\newlineChoose 11 answer:\newline(A) M(h)=30×(0.3)(h24)M(h)=30\times(0.3)^{\left(\frac{h}{24}\right)}\newline(B)M(h)=25×(0.3)(h24)M(h)=25\times(0.3)^{\left(\frac{h}{24}\right)}\newline(C) M(h)=25×(0.3)hM(h)=25\times(0.3)^{h}\newline(D) M(h)=25×(0.7)(h24)M(h)=25\times(0.7)^{\left(\frac{h}{24}\right)}

Full solution

Q. After 2424 hours, 30%30\% of a 2525 milligram dose of a new antibiotic remains in the body. Which of the following functions, MM, models the amount of the antibiotic (in milligrams) that remains in the body after hh hours?\newlineChoose 11 answer:\newline(A) M(h)=30×(0.3)(h24)M(h)=30\times(0.3)^{\left(\frac{h}{24}\right)}\newline(B)M(h)=25×(0.3)(h24)M(h)=25\times(0.3)^{\left(\frac{h}{24}\right)}\newline(C) M(h)=25×(0.3)hM(h)=25\times(0.3)^{h}\newline(D) M(h)=25×(0.7)(h24)M(h)=25\times(0.7)^{\left(\frac{h}{24}\right)}
  1. Given Information: We are given that 30%30\% of the antibiotic remains after 2424 hours. This means that after 2424 hours, the amount of antibiotic left is 30%30\% of the initial dose. We need to find a function that models this decay over time.
  2. Initial Dose: The initial dose of the antibiotic is 2525 milligrams. We need to express the remaining amount as a function of time, where time is measured in hours (h)(h).
  3. Percentage Calculation: Since 30%30\% remains after 2424 hours, we can express this as a percentage of the initial dose: 30%30\% of 2525 milligrams. To convert the percentage to a decimal, we divide by 100100: 30%=0.330\% = 0.3.
  4. Exponential Decay Function: The decay of the antibiotic in the body is exponential, and it can be modeled by an exponential decay function. The general form of an exponential decay function is M(h)=initial_amount×(decay_rate)(time/decay_time)M(h) = \text{initial\_amount} \times (\text{decay\_rate})^{(\text{time}/\text{decay\_time})}.
  5. Finding Decay Rate: We need to find the decay rate. After 2424 hours, 30%30\% of the antibiotic remains, so the decay rate must be such that when h=24h = 24, the function gives us 30%30\% of the initial dose. This means that the decay rate raised to the power of (24/24)(24/24) should equal 0.30.3.
  6. Decay Rate Calculation: The decay rate should be such that (decay_rate)1=0.3(\text{decay\_rate})^{1} = 0.3. Since raising any number to the power of 11 gives the number itself, the decay rate is 0.30.3.
  7. Writing the Function: Now we can write the function using the initial amount of 2525 milligrams and the decay rate of 0.30.3. The time hh will be divided by the period of decay, which is 2424 hours, to model the decay over time. This gives us the function M(h)=25×(0.3)(h/24)M(h) = 25 \times (0.3)^{(h/24)}.
  8. Matching the Function: Looking at the options provided, option (B) matches the function we derived: M(h)=25×(0.3)h24M(h) = 25 \times (0.3)^{\frac{h}{24}}. This function correctly models the amount of the antibiotic that remains in the body after hh hours, given that 30%30\% remains after 2424 hours.

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