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Let’s check out your problem:
Add.
\newline
5
10
\frac{5}{10}
10
5
+
+
+
3
10
\frac{3}{10}
10
3
=
=
=
_
_
_
_
\_\_\_\_
____
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Math Problems
Grade 7
Add and subtract fractions
Full solution
Q.
Add.
\newline
5
10
\frac{5}{10}
10
5
+
+
+
3
10
\frac{3}{10}
10
3
=
=
=
_
_
_
_
\_\_\_\_
____
Identify common denominator:
Identify the common denominator.
\newline
Both
fractions
have the same denominator,
10
10
10
, so no need to find a common denominator.
Add numerators:
Add the numerators.
5
10
+
3
10
=
(
5
+
3
)
10
=
8
10
\frac{5}{10} + \frac{3}{10} = \frac{(5 + 3)}{10} = \frac{8}{10}
10
5
+
10
3
=
10
(
5
+
3
)
=
10
8
Simplify fraction:
Simplify the
fraction
.
8
10
\frac{8}{10}
10
8
can be simplified to
4
5
\frac{4}{5}
5
4
by dividing both the numerator and the denominator by
2
2
2
.
More problems from Add and subtract fractions
Question
Find `x` value
\newline
2
x
−
2
=
0
2x-2=0
2
x
−
2
=
0
Get tutor help
Posted 8 months ago
Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
x
x
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Posted 8 months ago
Question
2
+
8
2+8
2
+
8
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Question
6
+
12
6+12
6
+
12
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Posted 8 months ago
Question
Multiply.
\newline
(
3
5
)
×
(
1
6
)
=
(\frac{3}{5})\times(\frac{1}{6})=
(
5
3
)
×
(
6
1
)
=
\newline
Submit
\newline
Get help
Get tutor help
Posted 8 months ago
Question
2
x
+
3
=
2
2x+3 = 2
2
x
+
3
=
2
\newline
Find
x
.
x.
x
.
Get tutor help
Posted 8 months ago
Question
Simplify to a single power of
3
3
3
:
\newline
3
5
×
3
2
3^{5} \times 3^{2}
3
5
×
3
2
\newline
Answer:
3
□
3 ^\square
3
□
Get tutor help
Posted 8 months ago
Question
Simplify to a single power of
6
6
6
:
\newline
6
3
⋅
6
2
6^{3} \cdot 6^{2}
6
3
⋅
6
2
\newline
Answer:
6
□
6 ^\square
6
□
Get tutor help
Posted 8 months ago
Question
What value of
z
z
z
makes the equation below true?
\newline
9
z
−
2
=
79
9 z-2=79
9
z
−
2
=
79
\newline
3
3
3
\newline
9
9
9
\newline
13
13
13
\newline
79
79
79
Get tutor help
Posted 8 months ago
Question
What value of
y
y
y
makes the equation below true?
\newline
5
y
+
2
=
17
5 y+2=17
5
y
+
2
=
17
\newline
2
2
2
\newline
3
3
3
\newline
6
6
6
\newline
17
17
17
Get tutor help
Posted 8 months ago
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