According to Descartes' Rule of Signs, can the polynomial function have exactly 1 positive real zero, including any repeated zeros? Choose your answer based on the rule only.g(x)=x4+5x3−9x2+9x+8Choices:(A)yes(B)no
Q. According to Descartes' Rule of Signs, can the polynomial function have exactly 1 positive real zero, including any repeated zeros? Choose your answer based on the rule only.g(x)=x4+5x3−9x2+9x+8Choices:(A)yes(B)no
Count Sign Changes: Count the number of sign changes in the coefficients of g(x)=x4+5x3−9x2+9x+8. Coefficients: 1,5,−9,9,8. Sign changes: 1 (from 5 to −9).
Descartes' Rule of Signs: According to Descartes' Rule of Signs, the number of positive real zeros is equal to the number of sign changes or less by an even number.Since we have 1 sign change, g(x) can have 1 or 0 positive real zeros.
Check Positive Real Zeros: Check if g(x) can have exactly 1 positive real zero.Since the possible number of positive real zeros is 1 or 0, it can have exactly 1 positive real zero.