According to Descartes' Rule of Signs, can the polynomial function have exactly 0 positive real zeros? Choose your answer based on the rule only.f(x)=x5+2x4+8x3−4x2+5Choices:(A)yes(B)no
Q. According to Descartes' Rule of Signs, can the polynomial function have exactly 0 positive real zeros? Choose your answer based on the rule only.f(x)=x5+2x4+8x3−4x2+5Choices:(A)yes(B)no
Count Sign Changes: Count the number of sign changes in the polynomial f(x)=x5+2x4+8x3−4x2+5. Coefficients: 1,2,8,−4,5. Sign changes: 1 (from 8 to −4).
Descartes' Rule of Signs: According to Descartes' Rule of Signs, the number of positive real zeros is equal to the number of sign changes or less by an even number.Since we have 1 sign change, the possible number of positive real zeros is 1 or 1−2=−1, which doesn't make sense, so we stick with 1.
Number of Positive Zeros: Since the polynomial can have 1 positive real zero, it cannot have exactly 0 positive real zeros.