According to Descartes' Rule of Signs, can the polynomial function have exactly 1 positive real zero, including any repeated zeros? Choose your answer based on the rule only.f(x)=x4+5x3+2x2−4x−5Choices:(A)yes(B)no
Q. According to Descartes' Rule of Signs, can the polynomial function have exactly 1 positive real zero, including any repeated zeros? Choose your answer based on the rule only.f(x)=x4+5x3+2x2−4x−5Choices:(A)yes(B)no
Count Sign Changes: Count the number of sign changes in the coefficients of f(x)=x4+5x3+2x2−4x−5. Coefficients: 1,5,2,−4,−5. Sign changes: 1 (from 2 to −4).
Descartes' Rule: According to Descartes' Rule of Signs, the number of positive real zeros is equal to the number of sign changes or less by an even number.Since we have 1 sign change, f(x) can have either 1 or 0 positive real zeros.
Determine Positive Zero: Determine if f(x) can have exactly 1 positive real zero.Since the possible number of positive real zeros is 1 or 0, it is possible for f(x) to have exactly 1 positive real zero.