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A variable needs to be eliminated to solve the system of equations below. Choose the correct first step.

{:[-2x-10 y=0],[6x-10 y=80]:}
Subtract to eliminate 
x.
Add to eliminate 
y.
Subtract to eliminate 
y.
Add to eliminate 
x.

A variable needs to be eliminated to solve the system of equations below. Choose the correct first step.\newline2x10yamp;=06x10yamp;=80 \begin{aligned} -2 x-10 y & =0 \\ 6 x-10 y & =80 \end{aligned} \newlineSubtract to eliminate x \mathbf{x} .\newlineAdd to eliminate y \mathbf{y} .\newlineSubtract to eliminate y \mathbf{y} .\newlineAdd to eliminate x \mathbf{x} .

Full solution

Q. A variable needs to be eliminated to solve the system of equations below. Choose the correct first step.\newline2x10y=06x10y=80 \begin{aligned} -2 x-10 y & =0 \\ 6 x-10 y & =80 \end{aligned} \newlineSubtract to eliminate x \mathbf{x} .\newlineAdd to eliminate y \mathbf{y} .\newlineSubtract to eliminate y \mathbf{y} .\newlineAdd to eliminate x \mathbf{x} .
  1. Given System of Equations: We are given the system of equations: {2x10y=0,6x10y=80}\{-2x - 10y = 0, 6x - 10y = 80\} To eliminate a variable, we need to look for coefficients that are the same or opposites. Here, the coefficients of yy are the same in both equations (10y-10y and 10y-10y). Therefore, we can eliminate yy by adding the two equations together.
  2. Eliminating a Variable: Let's add the two equations:\newline(2x10y)+(6x10y)=0+80(-2x - 10y) + (6x - 10y) = 0 + 80\newlineCombining like terms, we get:\newline(2x+6x)+(10y10y)=80(-2x + 6x) + (-10y - 10y) = 80\newline4x+0y=804x + 0y = 80
  3. Adding Equations: Since the yy terms have been eliminated, we are left with an equation in one variable:\newline4x=804x = 80\newlineThis confirms that adding the two equations was the correct first step to eliminate yy.