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A variable needs to be eliminated to solve the system of equations below. Choose the correct first step.

{:[4x+2y=12],[-x+2y=-28]:}
Subtract to eliminate 
y.
Add to eliminate 
x.
Add to eliminate 
y.
Subtract to eliminate 
x.

A variable needs to be eliminated to solve the system of equations below. Choose the correct first step.\newline4x+2y=12x+2y=28 \begin{array}{c} 4 x+2 y=12 \\ -x+2 y=-28 \end{array} \newlineSubtract to eliminate y \mathbf{y} .\newlineAdd to eliminate x \mathbf{x} .\newlineAdd to eliminate y \mathbf{y} .\newlineSubtract to eliminate x \mathbf{x} .

Full solution

Q. A variable needs to be eliminated to solve the system of equations below. Choose the correct first step.\newline4x+2y=12x+2y=28 \begin{array}{c} 4 x+2 y=12 \\ -x+2 y=-28 \end{array} \newlineSubtract to eliminate y \mathbf{y} .\newlineAdd to eliminate x \mathbf{x} .\newlineAdd to eliminate y \mathbf{y} .\newlineSubtract to eliminate x \mathbf{x} .
  1. Identify Coefficients: We have the system of equations:\newline4x+2y=124x + 2y = 12\newlinex+2y=28-x + 2y = -28\newlineTo eliminate a variable, we look for coefficients that are the same or opposites. Here, the coefficients of yy are the same in both equations (22 and 22). To eliminate yy, we would subtract one equation from the other.
  2. Subtract Equations: Subtract the second equation from the first one:\newline(4x+2y)(x+2y)=12(28)(4x + 2y) - (-x + 2y) = 12 - (-28)\newlineThis simplifies to:\newline4x(x)+2y2y=12+284x - (-x) + 2y - 2y = 12 + 28
  3. Simplify Equation: Simplify the equation:\newline4x+x+0=404x + x + 0 = 40\newlineThis further simplifies to:\newline5x=405x = 40
  4. Solve for x: Now we can solve for xx: x=405x = \frac{40}{5} x=8x = 8 However, we do not need to solve for xx to answer the question prompt. We only needed to identify the correct first step to eliminate a variable.