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A variable needs to be eliminated to solve the system of equations below. Choose the correct first step.

{:[8x-3y=49],[8x-6y=58]:}
Add to eliminate 
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Subtract to eliminate 
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Subtract to eliminate 
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Add to eliminate 
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A variable needs to be eliminated to solve the system of equations below. Choose the correct first step.\newline8x3y=498x6y=58 \begin{array}{l} 8 x-3 y=49 \\ 8 x-6 y=58 \end{array} \newlineAdd to eliminate x \mathbf{x} .\newlineSubtract to eliminate x \mathbf{x} .\newlineSubtract to eliminate y \mathbf{y} .\newlineAdd to eliminate y \mathbf{y} .

Full solution

Q. A variable needs to be eliminated to solve the system of equations below. Choose the correct first step.\newline8x3y=498x6y=58 \begin{array}{l} 8 x-3 y=49 \\ 8 x-6 y=58 \end{array} \newlineAdd to eliminate x \mathbf{x} .\newlineSubtract to eliminate x \mathbf{x} .\newlineSubtract to eliminate y \mathbf{y} .\newlineAdd to eliminate y \mathbf{y} .
  1. Given system of equations: We are given the system of equations:\newline{8x3y=498x6y=58 \begin{cases} 8x - 3y = 49 \\ 8x - 6y = 58 \end{cases} \newlineTo eliminate a variable, we need to make the coefficients of that variable the same in both equations and then either add or subtract the equations from each other. In this case, the coefficients of x x are already the same in both equations (both are 88), so we can eliminate x x by subtracting one equation from the other.
  2. Eliminate variable: Subtract the second equation from the first equation:\newline(8x3y)(8x6y)=4958 (8x - 3y) - (8x - 6y) = 49 - 58 \newline8x8x3y+6y=4958 8x - 8x - 3y + 6y = 49 - 58 \newline0x+3y=9 0x + 3y = -9 \newlineThis step eliminates x x and gives us an equation with only y y .