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A university endowment fund starts with $200,000\$200,000 and places it in an investment account with a 5.5%5.5\% interest rate compounded continuously to support future scholarships. How long will it take for the fund to grow to $350,000\$350,000??\newlineUse the formula A=PertA = Pe^{rt}, where AA is the balance (final amount), PP is the principal (starting amount), ee is the base of natural logarithms (2.71828)(\approx 2.71828), rr is the interest rate expressed as a decimal, and tt is the time in years.\newlineRound your answer to the nearest tenth.

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Q. A university endowment fund starts with $200,000\$200,000 and places it in an investment account with a 5.5%5.5\% interest rate compounded continuously to support future scholarships. How long will it take for the fund to grow to $350,000\$350,000??\newlineUse the formula A=PertA = Pe^{rt}, where AA is the balance (final amount), PP is the principal (starting amount), ee is the base of natural logarithms (2.71828)(\approx 2.71828), rr is the interest rate expressed as a decimal, and tt is the time in years.\newlineRound your answer to the nearest tenth.
  1. Identify values: Identify the values for PP, AA, rr, and tt. P=200,000P = 200,000 A=350,000A = 350,000 r=0.055r = 0.055
  2. Use formula and solve: Use the formula A=PertA = Pe^{rt} and solve for tt. 350,000=200,000imese0.055t350,000 = 200,000 imes e^{0.055t}
  3. Divide and simplify: Divide both sides by 200,000200,000. 350,000200,000=e0.055t\frac{350,000}{200,000} = e^{0.055t} 1.75=e0.055t1.75 = e^{0.055t}
  4. Take natural logarithm: Take the natural logarithm of both sides to solve for tt. ln(1.75)=0.055t\ln(1.75) = 0.055t
  5. Calculate ln(1.75) \ln(1.75) : Calculate ln(1.75) \ln(1.75) . ln(1.75)0.5596 \ln(1.75) \approx 0.5596
  6. Solve for t: Solve for tt. 0.5596=0.055t0.5596 = 0.055t t=0.55960.055t = \frac{0.5596}{0.055} t10.1745t \approx 10.1745
  7. Round to nearest tenth: Round to the nearest tenth. t10.2t \approx 10.2 years

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