A small country emits 70,000 kilotons of carbon dioxide per year. In a recent global agreement, the country agreed to cut its carbon emissions by 1.4% per year for the next 6 years. In the first year of the agreement, the country will keep its emissions at 70,000 kilotons and the emissions will decrease 1.4% in each successive year. How many total kilotons of carbon dioxide would the country emit over the course of the 6 year period, to the nearest whole number? Answer:

Question

A small country emits 70,000 kilotons of carbon dioxide per year. In a recent global agreement, the country agreed to cut its carbon emissions by  1.4% per year for the next 6 years. In the first year of the agreement, the country will keep its emissions at 70,000 kilotons and the emissions will decrease  1.4% in each successive year. How many total kilotons of carbon dioxide would the country emit over the course of the 6 year period, to the nearest whole number? Answer:

Bytelearn · Accepted Answer

Understand the problem: Understand the problem. We need to calculate the total carbon emissions over 6 years, with a 1.4% reduction each year after the first year.Calculate each year: Calculate the emissions for each year. The initial emission is 70,000 kilotons. For each subsequent year, we multiply the previous year's emissions by (1 - 0.014) to account for the 1.4% reduction.First year emissions: Calculate the emissions for the first year. In the first year, the emissions are 70,000 kilotons since there is no reduction.Second year emissions: Calculate the emissions for the second year. For the second year, we multiply the first year's emissions by (1 - 0.014) to find the reduced emissions. 70,000 * (1 - 0.014) = 70,000 * 0.986 = 69,020 kilotons.Third year emissions: Calculate the emissions for the third year. For the third year, we multiply the second year's emissions by (1 - 0.014). 69,020 * (1 - 0.014) = 69,020 * 0.986 ≈ 68,049.72 kilotons.Fourth year emissions: Calculate the emissions for the fourth year. For the fourth year, we multiply the third year's emissions by (1 - 0.014). 68,049.72 * (1 - 0.014) ≈ 68,049.72 * 0.986 ≈ 67,089.00 kilotons.Fifth year emissions: Calculate the emissions for the fifth year. For the fifth year, we multiply the fourth year's emissions by (1 - 0.014). 67,089.00 * (1 - 0.014) ≈ 67,089.00 * 0.986 ≈ 66,137.86 kilotons.Sixth year emissions: Calculate the emissions for the sixth year. For the sixth year, we multiply the fifth year's emissions by (1 - 0.014). 66,137.86 * (1 - 0.014) ≈ 66,137.86 * 0.986 ≈ 65,196.24 kilotons.Add up total emissions: Add up the emissions for all 6 years to get the total emissions. Total emissions = 70,000 (first year) + 69,020 (second year) + 68,049.72 (third year) + 67,089.00 (fourth year) + 66,137.86 (fifth year) + 65,196.24 (sixth year). Total emissions ≈ 70,000 + 69,020 + 68,049.72 + 67,089.00 + 66,137.86 + 65,196.24 ≈ 405,492.82 kilotons.Round total emissions: Round the total emissions to the nearest whole number. Total emissions ≈ 405,493 kilotons.

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